SOLUTION: Brandon and Chris together can do a piece of work in 12 days. After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days. In what time can each do the work
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-> SOLUTION: Brandon and Chris together can do a piece of work in 12 days. After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days. In what time can each do the work
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Question 1110819: Brandon and Chris together can do a piece of work in 12 days. After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days. In what time can each do the work? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Brandon and Chris together can do a piece of work in 12 days.
After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days.
In what time can each do the work?
:
let b = time required by Brandon working alone
let c = time required by Chris
Let the completed job = 1
:
Each will do a fraction of the work, the two fractions add up to 1
"Brandon and Chris together can do a piece of work in 12 days. + = 1
and
" After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days." + = 1
1 = 1 therefore + = +
combine like terms - = - =
cross multiply
7c = 14b
divide both sides by 7
c = 2b
:
replace c with 2b in the 1st equation + = 1
multiply by 2b
2(12) + 12 = 2b
24 + 12 = 2b
36 = 2b
b = 36/2
b = 18 days, Brandon alone
then
c = 2(18) = 36 days Chris alone
:
:
See if that works in the 2nd statement
"After Brandon has worked alone for 5 days, Chris finishes the work alone in 26 days. + = + = = 1
