SOLUTION: The polynomial of degree 4, P(x), has a root of multiplicity 2 at x=1 and roots of multiplicity 1 at x=0 and x=−2. It goes through the point (5,112).

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The polynomial of degree 4, P(x), has a root of multiplicity 2 at x=1 and roots of multiplicity 1 at x=0 and x=−2. It goes through the point (5,112).      Log On


   

Question 1110774: The polynomial of degree 4, P(x), has a root of multiplicity 2 at x=1 and roots of multiplicity 1 at x=0 and x=−2. It goes through the point (5,112).
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
P%28x%29=a%2Ax%28x%2B2%29%28x-1%29%5E2

You find a using the given point, for the formula solved for a.

112=a%2A5%2A%285%2B2%29%285-1%29%5E2
112=5%2A7%2A16%2Aa
a=112%2F%285%2A7%2A16%29
a=28%2F%285%2A7%2A4%29
a=1%2F5

highlight%28P%28x%29=%281%2F5%29x%28x%2B2%29%28x-1%29%5E2%29