SOLUTION: Sally bought some white envelopes at $.02 per envelope and some blue envelopes at $.035 per envelope. Total cost was $240.50. How many of each envelope did she buy? Most of thes

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Question 1110652: Sally bought some white envelopes at $.02 per envelope and some blue envelopes at $.035 per envelope. Total cost was $240.50. How many of each envelope did she buy?
Most of these types of problems contain the total number of envelopes bought.
This one doesn't.

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
w white envelopes
b blue envelopes

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some white envelopes at $.02 per envelope and some blue envelopes at $.035 per envelope. Total cost was $240.50.
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If that is all the description, then you can only account for the cost using what was given.

0.02w%2B0.035b=240.5
20w%2B35b=240500
highlight_green%284w%2B7b=48100%29-----------from here, you can look for any or all whole number solutions for points (w,b).

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


With only this information, you can't find a single solution. But you can find a finite set of solutions knowing that the numbers of white and blue envelopes must be whole numbers.

.02w+%2B+.035b+=+240.50
20w+%2B+35b+=+240500
4w+%2B+7b+=+48100

In this equation, 4w and 48100 are multiples of 4, so 7b must be a multiple of 4. Then, since 4 and 7 have no common factor, b must be a multiple of 4.

So b can be any multiple of 4 for which 7b is no more than 48100; and for each of those values of b the value of w is determined.

Note that each time you add 4 to the value of b, the value of w has to decrease by 7 for the sum of 4w and 7b to remain the same.

So to make a complete list of the solutions, you could start with b=0, which gives x=12025; then repeatedly increase b by 4 and decrease w by 7 until the value of w becomes negative.

(b,w) =
(0,12025)
(4,12018)
(8,12011)
(12,12004)
...
etc.