SOLUTION: A rocket accelerates from rest at the rate of 55 m/s^2 for 20 s. It then moves at a constant speed for 5 s after which it accelerates at -35 m/s^2 until it stops. What is the dista

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Question 1110637: A rocket accelerates from rest at the rate of 55 m/s^2 for 20 s. It then moves at a constant speed for 5 s after which it accelerates at -35 m/s^2 until it stops. What is the distance travelled during the slowing down period?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Accelerating from rest at the rate of 55m%22%2F%22s%5E2 for 20+s ,
the rocket would attain a speed of 55%2A20%22m+%2F+s%22=%221100+m+%2F+s%22 .
When it later decelerates with a constant -35m%22%2F%22s%5E2 acceleration,
it takes 1100%2F35s until it stops
During that slow down period the rocket's speed decreases linearly,
with an average speed of 1100%2F2%22m+%2F+s%22 .
During that period, travelling at that average velocity, it travels
%281100%2F2%29%281100%2F35%29m=1100%5E2%2F70m=highlight%28518571m%29 (rounded to the nearest meter).

NOTE: I can write formulas, so if you want them ask,
but I saw no need to complicate a simple way to the solution.