SOLUTION: Find the exact radian value of the reference angle of the given angle in radians with the works please , i'll appreciate it. θ =38π/11 θ = 4radians

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Question 1110588: Find the exact radian value of the reference angle of the given angle in radians with the works please , i'll appreciate it.
θ =38π/11
θ = 4radians

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
We like to "reference" an acute (or right) angle theta , such that 0%3C=theta%3C=pi%2F2 ,
because we can visualize such an angle in a right triangle.
So, when we find an angle that does not fit in that first quadrant interval,
we find a "symmetrical" reference angle in the first quadrant, because we know that, give or not a minus sign,
the trigonometric function values of both angles will be the same.

theta=38pi%2F11=%2833%2B5%29pi%2F11=33pi%2F11%2B5pi%2F11=3pi%2B5pi%2F11
5pi%2F11 is between 0 and 5.5pi%2F11=pi%2F2 ,
so it is less than a pi%2F2 right angle,
but 3pi is 1%261%2F2 counterclockwise turns,
or 6 quadrants.
The symmetrical reference angle, in the first quadrant is
%283pi%2B5pi%2F11%29-2pi-pi=highlight%285pi%2F11%29


The coordinates of Q%28cos%285pi%2F11%29%2Csin%285pi%2F11%29%29 and P%28-cos%285pi%2F11%29%2C-sin%285pi%2F11%29%29 have the same absolute value,
but with P being in the third quadrant,
both of the coordinates of P are negative.

pi=about3.14 and
3pi%2F2=about+4.71 ,
so theta=4 is in the third quadrant, with pi%3Ctheta%3C3pi%2F2 .
Just as before, for the third quadrant we add or subtract pi (a half turn),
as many times as needed,
until we get to the first quadrant.
The reference angle is 4-pi


NOTE:
For second quadrant, and fourt angles,
the first quadrant reference angle can be found,
by adding and/or subtracting pi as many times as needed
to get to an angle between pi%2F2 and pi
(in the second quadrant, but less than one whole turn),
and then subtracting that angle from pi to get the supplementary angle.
For example, 64pi%2F11=55pi%2F11%2B9pi%2F11=5pi%2B9pi%2F11 is
2%261%2F2%29%282pi%29 (or 2%261%2F2 counterclockwise turns, or 5 half turns)
plus 9pi%2F11 .
Subtracting those 5half-turns=5pi , we get 9pi%2F11 ,
with pi%2F2=5.5pi%2F11%3C9pi%2F11%3C11pi%2F11=pi .
Then, pi-9pi%2F11=2pi%2F11 is the first quadrant reference angle.