SOLUTION: A bag contain two white and three black balls. Obtain a probability distribution of the number of white balls if two balls are selected
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Question 1110584: A bag contain two white and three black balls. Obtain a probability distribution of the number of white balls if two balls are selected Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website! P(0 white) = (3/5)(2/4) = 6/20 = 3/10
P(1 white) = P(white then black) + P(black then white)
= (2/5)(3/4) + (3/5)(2/4) = 6/20 + 6/20 = 12/20 = 6/10
P(2 white) = (2/5)(1/4) = 2/20 = 1/10
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Check:
Since one of the above events MUST happen, the sum of their probabilities must be 1:
3/10 + 6/10 + 1/10 = 10/10 = 1 (ok)
