SOLUTION: I've been trying to figure this one out. The perimeter of the quadrilateral is 130 inches. Find the lengths of the sides. x+2 x-5 x^3-3x 2x+1 What's the formula for this

Algebra ->  Parallelograms -> SOLUTION: I've been trying to figure this one out. The perimeter of the quadrilateral is 130 inches. Find the lengths of the sides. x+2 x-5 x^3-3x 2x+1 What's the formula for this      Log On


   

Question 111038: I've been trying to figure this one out. The perimeter of the quadrilateral is 130 inches. Find the lengths of the sides.

x+2
x-5
x^3-3x
2x+1
What's the formula for this, please?
Found 2 solutions by checkley71, scott8148:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
A QUADRITATERAL IS ANY FIGURE WITH 4 SIDES OF ANY LENGTH.
IF THESE 4 TERMS ARE THE 4 SIDES THEN THE SUM OF THEM EQUALS 130 INCHES.
THUS:
X+2+X-5+X^3-3X+2X+1=130
X^3+X-2=130
X^3+X=132
X=APPROXIMATELY 5.02618
PROOF
5.02618^3+5.02618-2=130
126.97379+5.02618-2=130
129.999997=130
THUS THE SIDES ARE:
X+2=5.02618+2=7.02618
X-5=5.02618-5=.02618
X^3-3X=126.97379-15.07854=111.89523
2X+1=11.05236
7.02618+.02618+111.89523+11.05236=130
129.999997=130

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the perimeter is the sides added together

(x+2)+(x-5)+(x^3-3x)+(2x+1)=130 ___ x^3+x-132=0

this does not factor