SOLUTION: One car travels 62 miles per hour and another travels 48 miles per hour. If they start from the same place at the same time and travel in the same direction, after how many hours w

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Question 1110171: One car travels 62 miles per hour and another travels 48 miles per hour. If they start from the same place at the same time and travel in the same direction, after how many hours will the faster car be 42 miles ahead of the slower one?

Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Same idea; same method. Notice that effective separation rate is DIFFERENCE.

%2862-48%29%2Ax=42

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = distance traveled by the slower car
in +t+ hrs
+d+%2B+42+ = distance traveled by the faster car
in +t+ hrs
---------------------------------------------
Equation for slower car:
(1) +d+=+48t+
Equation for faster car:
(2) +d+%2B+42+=+62t+
------------------------
Plug (1) into (2)
+48t+%2B+42+=+62t+
+14t+=+42+
+t+=+3+
------------------------
In 3 hrs the faster car is 42 mi ahead of the slower car
------------------------
check:
(1) +d+=+48%2A3+
(1) +d+=+144+
and
(2) +d+%2B+42+=+62%2A3+
(2) +d+=+186+-+42+
(2) +d+=+144+
OK