SOLUTION: THE SPINNER SHOWN IS SPUN ONCE. DETERMINE THE PROBABILITY OF EACH EVENT. HOW LIEKLEY IS EACH EVENT. THE SPINNER IS NUMBERED 1-8. P(EVEN NUMBER) P(PRIME NUMBER) P(FACTOR OF

Algebra ->  Probability-and-statistics -> SOLUTION: THE SPINNER SHOWN IS SPUN ONCE. DETERMINE THE PROBABILITY OF EACH EVENT. HOW LIEKLEY IS EACH EVENT. THE SPINNER IS NUMBERED 1-8. P(EVEN NUMBER) P(PRIME NUMBER) P(FACTOR OF      Log On


   

Question 1110168: THE SPINNER SHOWN IS SPUN ONCE. DETERMINE THE PROBABILITY OF EACH EVENT. HOW LIEKLEY IS EACH EVENT. THE SPINNER IS NUMBERED 1-8.
P(EVEN NUMBER)
P(PRIME NUMBER)
P(FACTOR OF 12)
P(COMPOSITE NUMBER)
P(GREATER THAN 10)
P(NEITHER PRIME NOR COMPOSITE)
Found 2 solutions by Fombitz, math_helper:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let's define first.
Prime: Only factors are 1 and the number itself.
Composite: Not a prime number (also not 1).
The number one is neither prime nor composite.
Although you didn't mention, I'm assuming each of the numbers has an equal area so that the probabilities are identical for 1-8.
P%28Even%29=P%282%29%2BP%284%29%2BP%288%29=1%2F8%2B1%2F8%2B1%2F8=3%2F8
P%28Prime%29=P%282%29%2BP%283%29%2BP%285%29%2BP%287%29=4%281%2F8%29=1%2F2
P%28Factor_of_12%29=P%281%29%2BP%282%29%2BP%283%29%2BP%284%29%2BP%286%29=5%281%2F8%29=5%2F8
P%28Composite%29=1-P%281%29-P%28Prime%29=1-1%2F8-4%2F8=3%2F8
P%28N%3E10%29=0
P%281%29=1%2F8

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Just correcting P(even):