Question 1110145: If P(circle AND gray) = 0.24, P(circle) = 0.63, and P(gray) = 0.8, what is P(gray | circle)? Write your answer as a percent, rounded to the tenths place. (Don't forget the % sign at the end. If, in the process of rounding, you get a 0 for the tenths place, include the 0.) Remember to carefully use the Conditional Probability Formula
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
With only the given information, we can make one of two conclusions:
(1) There is required information that is missing; or
(2) the given information is not correct.
If P(circle)=0.63 and P(circle AND gray)=0.24, then P(circle AND NOT gray) is 0.62-0.24 = 0.39.
If P(gray)=0.8 and P(circle AND gray)=0.24, then P(NOT circle AND gray) = 0.8-0.24 = 0.56.
Then we have three mutually exclusive cases for which the sum of the probabilities is 0.24+0.39+0.56 = 1.19, which is impossible.
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