SOLUTION: AN AIRPLANE FLYING EAST AT THE RATE OF 6 MILES/MINUTES ,PASSED OVER A COURT-HOUSE AT 2 PM. A SECOND PLANE FLYING NORTH AT THE RATE OF 6 MILES/MINUTES,PASSED OVER THE COURT-HOUSE AT
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: AN AIRPLANE FLYING EAST AT THE RATE OF 6 MILES/MINUTES ,PASSED OVER A COURT-HOUSE AT 2 PM. A SECOND PLANE FLYING NORTH AT THE RATE OF 6 MILES/MINUTES,PASSED OVER THE COURT-HOUSE AT
Log On
Question 1109935: AN AIRPLANE FLYING EAST AT THE RATE OF 6 MILES/MINUTES ,PASSED OVER A COURT-HOUSE AT 2 PM. A SECOND PLANE FLYING NORTH AT THE RATE OF 6 MILES/MINUTES,PASSED OVER THE COURT-HOUSE AT 2:04 PM.IV THE PLANES ARE FLYING AT THE SAME ALTITUDE ,IN HOW MANY MINUTES AFTER 2 PM WILL THEY BE 36 MILES APART? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! AN AIRPLANE FLYING EAST AT THE RATE OF 6 MILES/MINUTES ,PASSED OVER A COURT-HOUSE AT 2 PM. A SECOND PLANE FLYING NORTH AT THE RATE OF 6 MILES/MINUTES,PASSED OVER THE COURT-HOUSE AT 2:04 PM. IV THE PLANES ARE FLYING AT THE SAME ALTITUDE,IN HOW MANY MINUTES AFTER 2 PM WILL THEY BE 36 MILES APART?
---------------
p = distance of the 1st plane from the courthouse at t minutes past 2
q = distance of the 2nd plane from the courthouse at t minutes past 2
-----
t=0 at 2:04
p = 6t + 4*6 = 6t+24
q = 6t
---
(6t+24)^2 + (6t)^2 = 36^2
(t+4)^2 + (t)^2 = 36
2t^2 + 8t -20 = 0