SOLUTION: Prove that the diagonals of a parallelogram bisect each other.

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Question 1109931: Prove that the diagonals of a parallelogram bisect each other.
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
If you draw it, the opposite sides are both equal and parallel
The alternate interior angles are equal.
At the diagonals, there are vertical angles, so those are equal.
One has opposite triangles formed with equal angles and 1 side equal as well. This is congruent by ASA.
Therefore, the diagonals are bisected by each other.

Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.
For the proof,  see the lesson
    - Properties of diagonals of parallelograms
in this site.


Also,  you have this free of charge online textbook on Geometry
    GEOMETRY - YOUR ONLINE TEXTBOOK
in this site.

The referred lessons are the part of this textbook under the topic "Properties of parallelograms".


Save the link to this online textbook together with its description

Free of charge online textbook in GEOMETRY
https://www.algebra.com/algebra/homework/Triangles/GEOMETRY-your-online-textbook.lesson

to your archive and use it when it is needed.