SOLUTION: A newspaper carrier has $6.65 in change. He has 5 more quarters than dimes but 4 times as many nickels as quarters. how many coins of each type does he have
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: A newspaper carrier has $6.65 in change. He has 5 more quarters than dimes but 4 times as many nickels as quarters. how many coins of each type does he have
Log On
Question 1109889: A newspaper carrier has $6.65 in change. He has 5 more quarters than dimes but 4 times as many nickels as quarters. how many coins of each type does he have Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! dimes=x
quarters=x+5
nickels=4(x+5) or 4x+20
.10x+.25(x+5)+.05(4x+20)=6.65
.10x+.25x+1.25+.20x+1.00=6.65
.55x=4.40, collecting terms and moving the constants to the right.
x=8 dimes (0.80)
x+5=13 quarters (3.25)
4(x+5)=52 nickels (2.60)
They add to $6.65