SOLUTION: 1080 feet of fencing farmer wants to enclosed three adjanent rectangular corrals the whole enclosed rectangle is 36,00 sq. feet. The rectangle at that top and bottom has 5440-2W

Algebra ->  Conversion and Units of Measurement -> SOLUTION: 1080 feet of fencing farmer wants to enclosed three adjanent rectangular corrals the whole enclosed rectangle is 36,00 sq. feet. The rectangle at that top and bottom has 5440-2W      Log On


   

Question 1109885: 1080 feet of fencing farmer wants to enclosed three adjanent rectangular corrals the whole enclosed rectangle is 36,00 sq. feet. The rectangle at that top and bottom has 5440-2W
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I believe what is meant (but not really clearly specified) is shown in the sketch below:



Numbers/variables below are meant to be lengths in feet and areas in square feet,
but I am not writing the units repeatedly.
fencinglength%22=%222L%2B4W%22=%221080 ,
so 2L=1080-4W --> L=%281080-4W%29%2F2 --> L=540-2W .
The total surface area is
36000=%28540-2W%29%2AW
36000=540W-2W%5E2
2W%5E2-540W%2B36000=0
Dividing everything by 2, we get the simplified, equivalent equation
W%5E2-270W%2B18000=0
Factoring to solve that equation, we get
%28W-150%29%28W-120%29=0 --> system%28W=120%2C%22or%22%2CW=150%29 .
So, either system%28W=120%2CL=36000%2F120%29 --> system%28W=120%2CL=300%29 , or
system%28W=150%2CL=36000%2F150%29 --> system%28W=150%2CL=240%29
That gives us two possible answers for the dimensions of "the whole enclosed rectangle."
Either the whole enclosed area is 120ft wide by 300ft long, or it is
150ft wide by 240ft long.