SOLUTION: a newspaper carrier has $7.10 in change. he has7 more quarters than dimes but five times as many nickels as quarters. how many coins of each type does he have?

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Question 1109884: a newspaper carrier has $7.10 in change. he has7 more quarters than dimes but five times as many nickels as quarters. how many coins of each type does he have?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a newspaper carrier has $7.10 in change. he has 7 more quarters than dimes but five times as many nickels as quarters. how many coins of each type does he have?
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Value Eq:: 5n+10d+25q = 710 cents
Quantity Eq:: q = d+7
Quantity Eq:: n = 5q
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Modify::
n + 2d + 5q = 142
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Substitute::
5q + 2(q-7) + 5q = 142
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12q = 142+14
12q = 156
q = 13 (# of quarters)
d = 13-7 = 6 (# of dimes)
n = 5q = 65 (# of nickels)
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Cheers,
Stan H.
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