SOLUTION: I need help figuring out how to solve this problem
The weight of a can of soup is jointly proportional to its height and to the square of its diameter.
A can 7 inches high wit
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The weight of a can of soup is jointly proportional to its height and to the square of its diameter.
A can 7 inches high wit
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Question 1109881: I need help figuring out how to solve this problem
The weight of a can of soup is jointly proportional to its height and to the square of its diameter.
A can 7 inches high with a diameter of 2 inches weighs 11.1 ounces. What is the weight of a can that is 4 inches with a diameter of 4 inches.
The weight of the can is how many ounces? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The weight of a can of soup is jointly proportional to its height and to the square of its diameter.
w = k*h*d^2
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Solve for "k" using "A can 7 inches high with a diameter of 2 inches weighs 11.1 ounces.
11.1 = k*7*2^2
11.1 = 28k
k = 0.3964
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Equation::
w = 0.3964*h*d^2
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What is the weight of a can that is 4 inches high with a diameter of 4 inches.
The weight of the can is how many ounces?
w = 0.3964*4*4^2 = 25.37 ounces
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Cheers,
Stan H.
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