SOLUTION: The growth of a colony of 800 bacteria can be modelled by N=800(2)^t/3 in which N is the number of bacteria after t hours how many bacteria are present after 12.7 hours

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Question 1109783: The growth of a colony of 800 bacteria can be modelled by N=800(2)^t/3 in which N is the number of bacteria after t hours how many bacteria are present after 12.7 hours
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+N+=+800%2A2%5E%28t%2F3%29+
+t+=+12.7+ hrs
+N+=+800%2A2%5E%2812.7%2F3%29+
+N+=+800%2A2%5E4.2333+
+N+=+800%2A18.8088+
+N+=+15047+
There are 15,047 bacteria after 12.7 hrs
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check:
+15047+=+800%2A2%5E%28t%2F3%29+
+2%5E%28t%2F3%29+=+18.8088+
+%28t%2F3%29%2Alog%282%29+=+log%28+18.8088+%29+
+%28t%2F3%29%2A.30103+=+1.27436+
+t%2F3+=+4.23333+
+t+=+12.70001+
close enough