SOLUTION: A survey of the most requested song in a radio program in the region shows that 95 out of 150 men like the song requested, while 110 out of 200 women like the song requested. A res

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Question 1109773: A survey of the most requested song in a radio program in the region shows that 95 out of 150 men like the song requested, while 110 out of 200 women like the song requested. A researcher wants too decide whether the difference between the two proportions. 95/150=0.63 and 110/200=0.55 is significant or not at 5% level of significance.
Answer by stanbon(75887) About Me  (Show Source):
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A survey of the most requested song in a radio program in the region shows that 95 out of 150 men like the song requested, while 110 out of 200 women like the song requested. A researcher wants too decide whether the difference between the two proportions. 95/150=0.63 and 110/200=0.55 is significant or not at 5% level of significance.
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Ho: p1-p2 = 0
Ha:: p1-p2 # 0
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sample difference:: 0.63-0.55 = 0.08
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Z(0.08) = 0.08/sqrt[[0.63*0.37]/150 + [0.55*0.45]/200] = 1.514
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p-value = 2*P(z > 0.135) = 2*normalcdf(1.514,100) = 0.13
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Conclusion:: Since the p-value is greater than 5% fail
to reject Ho.
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Cheers,
Stan H.
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