SOLUTION: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange. Sam invested a total of $10,000, part at 8% and the rest a

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange. Sam invested a total of $10,000, part at 8% and the rest a      Log On

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Question 110975: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange.

Sam invested a total of $10,000, part at 8% and the rest at 3%. How much was invested at 8% if he earned a total of $600 in one year? (Use the formula , Interest = principal * time * rate)
These are very confusing


Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=oranges and a=apples ___ 12x+7a=536 ___ 8x+5a=368

multiplying the first equation by 5 gives 60x+35a=2680
multiplying the second equation by -7 gives -56x-35a=-2576

adding the resulting equations gives 4x=104



let x="amount @ 8%", so 10000-x="amount @ 3%" ___ x(8%)+((10000-x)(3%))=600

.08x+300-.03x=600 ___ .05x=300