SOLUTION: How to factor 64x^6 - 1 completely? 4/3(6x-3) = 3/4(8x-12) Solve for x: -2/9x + 2/45 = 2/5

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Question 1109657: How to factor 64x^6 - 1 completely?

4/3(6x-3) = 3/4(8x-12)

Solve for x:
-2/9x + 2/45 = 2/5
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
4%2F3%286x-3%29+=+3%2F4%288x-12%29+

Maybe you really mean, %284%2F3%29%286x-3%29+=+%283%2F4%29%288x-12%29+?

16%286x-3%29=9%288x-12%29
Look at the factors on each side carefully,...


16%2A3%2A%282x-1%29=9%2A4%2A%282x-3%29

4%282x-1%29=3%282x-3%29

8x-4=6x-9

cross%282x=13%29

cross%28x=13%2F2=6%261%2F2%29
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EASIER THAN THAT:
%284%2F3%29%286x-3%29+=+%283%2F4%29%288x-12%29+
%284%2F3%29%2A3%282x-1%29=%283%2F4%29%2A4%282x-3%29
4%282x-1%29=3%282x-3%29
8x-4=6x-9
2x-4=-9
2x=-5
highlight%28x=-5%2F2%29

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You can figure out the last equation, and the first expression you asked for factorization shows Difference Of Squares.