SOLUTION: The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet.
If a rock
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-> SOLUTION: The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet.
If a rock
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Question 110964: The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet.
If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information. Typing hint: Type t-squared as t^2
How high is the rock after 1 second?
After how many seconds will the graph reach maximum height?
What is the maximum height? Answer by scott8148(6628) (Show Source):
this is the equation of a parabola ___ the maximum (or minimum) lies on the axis of symmetry
the general equation for the axis of symmetry is x=-b/2a
___ in this case, t=-v0/(2(-16)) ___ this is the time to maximum height
___ plugging this t into the equation will give the maximim height
