Question 1109610: An airplane encountered a head wind during a flight between Joppetown and Jawsburgh which took 5 hours and 24 minutes. The return flight took 5 hours. If the distance from Joppetown to Jawsburgh is 2700 miles, find the airspeed of the plane (the speed of the plane in still air) and the speed of the wind, assuming both remain constant.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! velocity * time=distance
V (going)*5.4 hours=2700 miles, so V (going)=500 mph.
V(return)*5 hours=2700 miles, so V(return)=540 mph
velocity=p-w with headwind, p plane, w wind
p+w with tail wind
p+w=540
p-w=500, add them
2p=1040
p=520 mph plane
w=20 mph wind
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