SOLUTION: Suppose that the manufacturer of a DVD player has found​ that, when the unit price is p​ dollars, the revenue R​ (in dollars) as a function of the price p is
R(
Question 1109607: Suppose that the manufacturer of a DVD player has found that, when the unit price is p dollars, the revenue R (in dollars) as a function of the price p is
R(p)=-2.5p^2+850p
(a) For what price will the revenue be maximized?
(b) What is the maximum revenue? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! R=-2.5p^2+850 p
This is a quadratic where the vertex is the maximum value.
vertex p value is -b/2a=-850/-2.5*2=+170 so $170 is price at maximum revenue
R=-2.5*170^2+850*170
=-72250+144500
=$72,250
