SOLUTION: The rectangle shown has a perimeter of 112 cm and the given area. Its length is 6 more than four times its width. Write and solve a system of equations to find the dimensions of th

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Question 1109579: The rectangle shown has a perimeter of 112 cm and the given area. Its length is 6 more than four times its width. Write and solve a system of equations to find the dimensions of the rectangle.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I do not need "the given area" or a system of equations.
I do not even need to write an equation to see that
it is a 46cm by 10cm rectangle. It is as y mental math.
The equation I would write (if someone asked for one) is
2x%2B2%284x%2B6%29=112 where x is the width in cm.
Of course, length is 4x%2B6 (6 more than 4 times the width).

Maybe the system of equations you ate expected to write is
system%282L%2B2W=112%2CL=4W%2B6%29 ,
with L and W being length and with respectively.
To solve,
you would substitute %284W%2B6%29 for L in 2L%2B2W=112
to get 2%284W%2B6%29%2B2W=112 ,
8W%2B12%2B2W=112 ,
10W%2B12=112 ,
10W=112-12 ,
10W=100 ,
W=110%2F10 , and
highlight%28W=10%29 .
Then, substituting 10 for W in L=4%2B6 ,
you would find
L=4%2A10%2B6 , L=40%2B6 a,d highlight%28L=46%29 .