SOLUTION: The rectangle shown has a perimeter of 112112 cm and the given area. Its length is 66 more than four timesfour times its width. Write and solve a system of equations to find the di

Algebra ->  Average -> SOLUTION: The rectangle shown has a perimeter of 112112 cm and the given area. Its length is 66 more than four timesfour times its width. Write and solve a system of equations to find the di      Log On


   

Question 1109578: The rectangle shown has a perimeter of 112112 cm and the given area. Its length is 66 more than four timesfour times its width. Write and solve a system of equations to find the dimensions of the rectangle.
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
What given area?
112112 cm perimeter?
Maybe 112 centimeters perimeter?
2L%2B2w=112
2%284w%2B66%29%2B2w=112
4w%2B66%2Bw=56
5w=56-66
5w=-10-------------not good; w needs to be postive; not negative.

Trying again:
L=4w+66, and w, the dimensions;
2L%2B2w=112
L%2Bw=56
4w%2B66%2Bw=56
5w=-10--------w=-2---------no good.


***Your given perimeter was what is intended?***
L%2Bw=56056
4w%2B66%2Bw=56056
5w=55990
w=11198------width
-
L=44858-----length

check perimter:
2%2811198%2B44858%29
112112, okay%7D%7D%2C%7B%7B%7Bchecks