SOLUTION: As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the ball

Algebra ->  Functions -> SOLUTION: As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the ball      Log On


   



Question 1109367: As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the balloon after 4 seconds.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the balloon after 4 seconds.
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V+=+4pi%2Ar%5E3%2F3
dV/dt = 4pi*r^2*dr/dt --- 1st derivative
dV/dt = 16pi*r^2 cc/sec
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If you mean 4 seconds after its volume was zero:
V+=+4pi%2Ar%5E3%2F3+=+4pi%2A16%5E3%2F3
= 16384*pi/3 cc