SOLUTION: maggie won 10,000 in a baking contest and decided to invest her winning in stocks and bonds, where stocks yielded 8% and yielded 6% annual interest. if the total interest she earn

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Question 1109355: maggie won 10,000 in a baking contest and decided to invest her winning in stocks and bonds, where stocks yielded 8% and yielded 6% annual interest. if the total interest she earned at the end of one year was $720, how much did she invest in each?
thanks!

Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Use simple interest formula, +I+=+P%2Ar%2At+
(1) +I+=+P%2A.08%2A1+
(2) +720+-+I+=+%28+10000+-+P+%29%2A.06%2A1+
------------------------------------------
(1) +I+=+.08P+
(2) +720+-+I+=+600+-+.06P+
(2) +I+=+.06P+%2B+120+
-------------------------------
Plug (1) into (2)
(2) +.08P+=+.06P+%2B+120+
(2) +.02P+=+120+
(2) +P+=+6000+%7D%0D%0Aand%0D%0A%7B%7B%7B+10000+-+P+=+10000+-+6000+
+10000+-+P+=+4000+
--------------------------------
Maggie invested $6,000 in stocks
and $4,000 in bonds
--------------------------------
check:
(2) +720+-+I+=+%28+10000+-+P+%29%2A.06%2A1+
(2) +720+-+I+=+4000%2A.06%2A1+
(2) +720+-+I+=+240+
and
(1) +I+=+P%2A.08%2A1+
(1) +I+=+.08%2A6000+
(1) +I+=+480+
and
+240+%2B+480+=+720+ as it should


Answer by greenestamps(13214) About Me  (Show Source):
You can put this solution on YOUR website!


The algebraic solution provided by the other tutor is of course fine; it is the standard method for solving "mixture" problems.

But try this much faster method and see if you like it....

(1) The $720 interest on the $10,000 investment represents a return of 7.2%.
(2) 7.2% is (1.2/2) = 3/5 of the way from 6% to 8%.
(3) So 3/5 of the money was invested at 8%.

Answer: 3/5 of $10,000, or $6000, at 8%; the rest, $4000, at 6%.