SOLUTION: Henry and Harriet are running around an oval that has a perimeter of 400m. Henry takes two and a half minutes to run a full lap while Harriet takes two minutes to run a full lap. I

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Question 1109352: Henry and Harriet are running around an oval that has a perimeter of 400m. Henry takes two and a half minutes to run a full lap while Harriet takes two minutes to run a full lap. If they both start at the same time and run in the same direction, how long will it take Harriet to lap Henry?
Found 2 solutions by KMST, ikleyn:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Henry's speed is 400m%2F%222.5+minutes%22=160m%2Fminute .
Harriet's speed is 400m%2F%222+minutes%22=200m%2Fminute .
in x minutes Henry will have run 160x meters,
and Harriet will have run 200x meters.
When Harriet laps Henry,
she will have run 400m (one full lap) longer than Henry.
That translates as
200x=160x%2B400 .
Solving that equation:
200x=160x%2B400
200x-160x=400
40x=400
x=400%2F40
x=10 .
It seems to be that Harriet will lap Henry after highlight%2810+minutes%29 .
Let's verify.
In 10 minutes Harry will have run 4laps=10minutes%2F%222.5+minutes%22 ,
and Harrriet will have run 5laps=10minutes%2F%222+minutes%22 .

NOTE: We did not need to know the size of the track, because we could have measure their speeds in laps per minute instead of meters per minute.
For this particular problems, we could also have figured out the answer by listing how long it took for Henry and for Harriet to run 1, 2, 3, 4, 5, ... laps.
For Henry:
.
For Harriet:
.
It would not have been so easy, if Harriet had lapped Henry after 4.3 laps for Henry and 5.3 laps for Harriet.

Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let L be the "oval perimeter" length.

    The condition says that L = 400 meters.
    But in reality, with all other given data, the solution below is VALID for any value of L: it DOES NOT DEPEND on the concrete value of L

1. Short Physics solution

     Henry'   speed is  L%2F2.5  units of L per minute.

     Harriet' speed is  L%2F2 units of L per minute.

     The relative speed is  L%2F2+-+L%2F2.5 = L%2A%281%2F2+-+1%2F2.5%29 = 2L%2A%28%281%2F4%29-%281%2F5%29%29 = 2L%2A%285%2F20-4%2F20%29 = %282L%29%2A%281%2F20%29 = L%2F10 units of L per minute.


     It means that after start, the distance between Harriet (who runs faster) and Henry will increase at the rate of L%2F10 per minute.


     Hence, Harriet will win one lap in 10 minutes.


     Notice that the solution does not depend on the concrete value of L.

2. - Algebra solution

     The distance along the oval from the starting point is

        D1 = %28L%2F2.5%29%2At for Henry   (=speed*time)

        D2 = %28L%2F2%29%2At for Harriet.


     The condition  D2 -D1 = L  is

        %28L%2F2%29%2At+-+%28L%2F2.5%29%2At = L,

        %28L%2F4+-+L%2F5%29%2A2t = L,

        %285L%29%2F20+-+%284L%29%2F20%29%2A2t = L,

        %28L%2F20%29%2A2t = L,

        %28L%2F10%29%2At = L

     and gives, finally, the same answer  t = L%2F%28%28L%2F10%29%29 = 10 minutes.

Solved.

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To see many other similar  (or closely related)  solved problems,  look into the lesson
    - Problems on bodies moving on a circle
in this site.