SOLUTION: an aircraft carrier made a trip to dry dock and back. it took 11 hours to get there and 8 hours to get back. the aircraft averaged 22 mph on the return trip. what was it’s speed g

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: an aircraft carrier made a trip to dry dock and back. it took 11 hours to get there and 8 hours to get back. the aircraft averaged 22 mph on the return trip. what was it’s speed g      Log On

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Question 1109328: an aircraft carrier made a trip to dry dock and back. it took 11 hours to get there and 8 hours to get back. the aircraft averaged 22 mph on the return trip. what was it’s speed going to dry dock?
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
the distance in each way is the same:


11*v = 22*8     (each way distance),


where v is the unknown rate.  From the equation,


v = %2822%2A8%29%2F11 = 16 miles per hour was the average rate on the way to the dock.