SOLUTION: A chemist wants to get a 50% acid solution by mixing 8 liters of 60% acid solution with 20% acid solution. How much 20% solution does the chemist need?

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Question 1109160: A chemist wants to get a 50% acid solution by mixing 8 liters of 60% acid solution with 20% acid solution. How much 20% solution does the chemist need?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of 20% solution needed
+.2x+ = liters of acid in 20% solution
+.6%2A8+=+4.8+ = liters of acid in 60% solution
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+%28+.2x+%2B+4.8+%29+%2F+%28+x+%2B+8+%29+=+.5+
+.2x+%2B+4.8+=+.5%2A%28+x+%2B+8+%29+
+.2x+%2B+4.8+=+.5x+%2B+4+
+.3x+=+.8+
+x+=+2.667+
2.667 liters of 20% solution are needed
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check:
+%28+.2x+%2B+4.8+%29+%2F+%28+x+%2B+8+%29+=+.5+
+%28+.2%2A2.667+%2B+4.8+%29+%2F+%28+2.667+%2B+8+%29+=+.5+
+%28+.5333+%2B+4.8+%29+%2F+10.667+=+.5+
+5.333+=+.5%2A10.667+
+5.333+=+5.333+
OK