SOLUTION: Can someone help with this.
the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable
Algebra ->
Rational-functions
-> SOLUTION: Can someone help with this.
the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable
Log On
Question 1109083: Can someone help with this.
the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diamter of .5 inches Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diameter of .5 inches
====
R = k*L/d^2
Solve for "k"::
8 = k*8/1^2
k = 64
-----
R = 64*L/d^2
-----
R = 64*20/(0.5)^2 = 64*20/(1/4) = 64*80 = 5120 ohms
-----------
Cheers,
Stan H.
----------
---
(