Question 1109047: Several years ago, 41% of parents who had children in grades K-12 were
satisfied with the quality of education the students receive. A recent poll
were asked 1,105 parents who have children in grades K-12 if they were
satisfied with the quality of education the students receive. Of the 1,105
surveyed, 456 indicated that they were satisfied. Construct a 90% confidence
interval to assess whether this represents evidence that parents' attitudes
toward the quality of education have changed.
What are the null and alternative hypotheses?
The Answer Is [Upper H 0: p= 0.41 versus H 1: p is not equal 0.41]
How do you find what the lower bound number is and what the upper bound number is if the confidence interval 90% . (Please show steps , especially if using TI-84 Calculator)
The lower bound is =
The upper bound is =
(Round to two decimal places as needed.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Several years ago, 41% of parents who had children in grades K-12 were
satisfied with the quality of education the students receive.
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A recent poll were asked 1,105 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,105
surveyed, 456 indicated that they were satisfied.
-----------------------
Construct a 90% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.
What are the null and alternative hypotheses?
The Answer Is [Upper H 0: p= 0.41 versus H 1: p is not equal 0.41]
How do you find what the lower bound number is and what the upper bound number is if the confidence interval 90% . (Please show steps , especially if using TI-84 Calculator)
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A 90% CI is centered at p or at u.
Each of the tails is 5%.
The boundary z-value of the left tail is as follows::
(Using TI-84+)
2nd DIST
invNorm(0.05) = -1.645
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Because of symmetry the boundary of the right tail is +1.645
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Now find the corresponding proportion values::
(Using TI-84+)
Lower boundary = 0.41-1.645*sqrt(0.41*0.59/1105) = 0.3857
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The upper bound is = 0.41+1.645*sqrt(0.41*0.59/1105) = 0.4343
(Round to two decimal places as needed.)
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Cheers,
Stan H.
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