SOLUTION: An observer stands 150 ft. away from a building. His eye level is 6 ft above the ground. From his eye level, he measures the angle of elevation to the top of the building to be 53

Algebra ->  Angles -> SOLUTION: An observer stands 150 ft. away from a building. His eye level is 6 ft above the ground. From his eye level, he measures the angle of elevation to the top of the building to be 53       Log On


   

Question 1108903: An observer stands 150 ft. away from a building. His eye level is 6 ft above the ground. From his eye level, he measures the angle of elevation to the top of the building to be 53 degrees. Find the height of the building. Round to nearest foot.
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
system%28150%2Asin%2853%29%2Fcos%2853%29%2B6%2Cor%2C150%2Atan%2853%29%2B6%29

y, vertical disance up building without the 6 feet of observer's height
r, distance from observer eyes to top of building

cos%2853%29=150%2Fr
r=150%2Fcos%2853%29
-
y%2Fr=sin%2853%29
y=r%2Asin%2853%29
y=%28150%2Fcos%2853%29%29%2Asin%2853%29
y=150%28sin%2853%29%2Fcos%2853%29%29
-
Looking for y%2B6;