SOLUTION: Solve the problem by setting up and solving an appropriate algebraic equation. Suppose that the length of a certain rectangle is 5 meters less than two times its width. The perime

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Question 1108864: Solve the problem by setting up and solving an appropriate algebraic equation.
Suppose that the length of a certain rectangle is 5 meters less than two times its width. The perimeter of the rectangle is 44 meters. Find the length and width of the rectangle.
length
width

Answer by addingup(3677) About Me  (Show Source):
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Length = 2W - 5
2L + 2W = 44 substitute for L with above:
2(2W - 5) + 2W = 44
Distributive property of multiplication:
4W - 10 + 2W = 44
6W - 10 = 44
6W = 54
W = 9
and
L = 2W - 5 = 2(9) - 5 = 18 - 5 = 13
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Check:
2L + 2W = 44
2(13) + 2(9) = 44
26 + 18 = 44 Correct