SOLUTION: Write the first 5 terms of the sequence:
a_(1)=1
a_(2)=0
a_(n)= a_(n-1)-a_(n-2)
For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a_(5) I get 2.
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-> SOLUTION: Write the first 5 terms of the sequence:
a_(1)=1
a_(2)=0
a_(n)= a_(n-1)-a_(n-2)
For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a_(5) I get 2.
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Question 1108733: Write the first 5 terms of the sequence:
a_(1)=1
a_(2)=0
a_(n)= a_(n-1)-a_(n-2)
For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a_(5) I get 2.
Key:
a_(#) in words means "a sub #". Answer by greenestamps(13200) (Show Source):
You should be able to see your mistake if you look at the work you did. Or maybe it would be better to start over on the problem. Often if you make a mistake and try to find it by looking at the work you did, you automatically make the same mistake again.
Here is what you show:
a(1) = 1
a(2) = 0
a(3) = a(2)-a(1) = 0-1 = -1 (looks good)
a(4) = a(3)-a(2) = -1-0 = -1 (still looks good)
a(5) = a(4)-a(3) = -1-(-1) = 2 (how about that one -- does it still look good to you?)