SOLUTION: Box contains 78 coins. Only dimes and nickels. Total amount in box $5.90. How many dimes and how many nickels are in box?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Box contains 78 coins. Only dimes and nickels. Total amount in box $5.90. How many dimes and how many nickels are in box?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1108661: Box contains 78 coins. Only dimes and nickels. Total amount in box $5.90. How many dimes and how many nickels are in box?
Found 2 solutions by josgarithmetic, addingup:
Answer by josgarithmetic(39630) About Me  (Show Source):
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
d + n = 78 subtract n from both sides
d = 78 - n
0.10d + 0.05n = 5.90 substitute for d:
0.10(78 - n) + 0.05n = 5.90
7.80 - 0.10n + 0.05n = 5.90
7.80 - 0.05n = 5.90
- 0.05n = - 1.90
n = 38 so there are 38 nickels and 78 - 38 = 40 dimes
-----------------------
Check:
38(0.05) + 40(0.10) = 5.90 Correct