SOLUTION: Find the x and y- intercepts, if they exist. -4x + 8y =12

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Question 110857: Find the x and y- intercepts, if they exist. -4x + 8y =12
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

-4%2Ax%2B8%2Ay=12 Start with the given equation

Let's find the x-intercept

To find the x-intercept, let y=0 and solve for x:
-4%2Ax%2B8%2A%280%29=12 Plug in y=0

-4%2Ax=12 Simplify

x=12%2F-4 Divide both sides by -4


x=-3 Reduce



So the x-intercept is (note: the x-intercept will always have a y-coordinate equal to zero)



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-4%2Ax%2B8%2Ay=12 Start with the given equation

Now let's find the y-intercept

To find the y-intercept, let x=0 and solve for y:
-4%2A%280%29%2B8%2Ay=12 Plug in x=0

-8%2Ay=12 Simplify

x=12%2F8 Divide both sides by 8



y=3%2F2 Reduce



So the y-intercept is (note: the y-intercept will always have a x-coordinate equal to zero)

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So we have these intercepts:
x-intercept:

y-intercept:



Now plot the two points and (which is the point (0,1.5) in decimal form)




Now draw a line through the two points to graph -4%2Ax%2B8%2Ay=12
graph of -4%2Ax%2B8%2Ay=12 through the points and