SOLUTION: If three numbers from 100 to 999 are chosen at random, one at a time, find the probability that they will be chosen in increasing order.
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-> SOLUTION: If three numbers from 100 to 999 are chosen at random, one at a time, find the probability that they will be chosen in increasing order.
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Question 1108503: If three numbers from 100 to 999 are chosen at random, one at a time, find the probability that they will be chosen in increasing order. Answer by ikleyn(52805) (Show Source):
If three numbers from 100 to 999 are chosen at random, there is ONLY ONE permutation / arrangement to get them in increasing order
against 6 = 3! of possible arrangements.
So, the probability under the question is .
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I assume (although the problem does not state it explicitly) that every time three different numbers are chosen at random.
