SOLUTION: I still didn't get an answer for this one. It's not a typo, as far as I know, but I can't get started on it. Solve the following exponential equation: 49 over(/) 1-1e^3x = 6

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I still didn't get an answer for this one. It's not a typo, as far as I know, but I can't get started on it. Solve the following exponential equation: 49 over(/) 1-1e^3x = 6      Log On


   

Question 110850: I still didn't get an answer for this one. It's not a typo, as far as I know, but I can't get started on it.
Solve the following exponential equation:
49 over(/) 1-1e^3x = 68
If there's a typo, it could be 1-1e^3x is supposed to be read 1-1e_3x, but the 3x definitely looks like a little exponent and not a base.
Found 2 solutions by scott8148, MathLover1:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
multiplying by (1-1e^3x) and dividing by 68 gives 49/68=1-1e^3x

subtracting 1 and multiplying by -1 gives 19/68=e^3x

taking the natural log gives ln(19/68)=3x

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
49+%2F%28+1-1e%5E3x%29+=+68…..multiply both sides by %28+1-1e%5E3x%29
%2849+%2F%281-1e%5E3x%29%29%2A%28+1-1e%5E3x%29=+68%28+1-1e%5E3x%29
49+=+68%28+1-1e%5E3x%29..........divide both sides by 68
49%2F68+=+68%2F68%28+1-1e%5E3x%29.........
0.72=+1-1e%5E3x..........
+ln+0.72++=+1+-3x..........move -3x to the left and ln.72 to the right
3x+=+1+-+ln+.72..........
3x+=+1+-0.33
3x+=+1+-0.33
3x+=+0.67
x+=+0.67%2F3
x+=+0.2233