Question 1108482: Solve the following system of linear equations using the substitution method:
Express answer as an ordered pair.
Found 2 solutions by asymptote, TeachMath:
Answer by asymptote(2)   (Show Source):
You can put this solution on YOUR website! Solve for y in the first equation, then plug this expression into the second equation and solve for x:
1) Add x term to both sides: 
2) Divide both sides by 3/2 (a.k.a multiply by reciprocal, 2/3) to isolate y: 
3) Now substitute this expression for y in the second equation:
4) Simplify left-hand side by distributing 1/3 in preparation of isolating x:
5) Combine x terms by using common denominator of 72:
6) Subtract 22/9 from both sides by using common denominator of 9:
7) Solve for x by multiplying both sides by -72/5 (a.k.a dividing by -5/72):
We now know x and can plug -8 into either of the original two equations and solve for y. I will use the second equation:
1) 
2) 
3) 
4) 
When we plug x = -8 and y = 6 back into both original equations, we get true equalities, verifying our answer.
Finally, writing as ordered pair, (x,y) yields (-8, 6) as our final answer.
Just as a note, unless you had to solve this by substitution, I would recommend using the elimination method as it would be much quicker.
Answer by TeachMath(96) (Show Source):
You can put this solution on YOUR website! – ¼x + (3/2)y = 11
(– 1/8)x + (1/3)y = 3
Multiply eq 1 by - 4 to get: x - 6y = - 44____x = 6y - 44
Multiply eq 2 by LCD, 24 to get: - 3x + 8y = 72
Then substitute 6y - 44 for x in the equation: - 3x + 8y = 72
This should give you a y-value of 6
Substitute 6 for y in any of the 2 original equations to get an x-value of - 8.
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