SOLUTION: The length of a rectangle is 4 inches more than twice the width. If the perimeter is 88 inches, what is the length and width of the rectangle?

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Question 1108104: The length of a rectangle is 4 inches more than twice the width. If the perimeter is 88 inches, what is the length and width of the rectangle?

Found 3 solutions by josgarithmetic, Shin123, ikleyn:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website!

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Answer by Shin123(626)   (Show Source):
You can put this solution on YOUR website!
88 inches/ 4 sides=length+width of rectangle= 22 inches 22-4=18 18/2=the width=9 in. 9+4=length=13 in. The length is 13 in. and the width is 9 in.

Answer by ikleyn(52802)   (Show Source):
You can put this solution on YOUR website!
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L = 2W +4 The perimeter equation is L + W + L + W = 88, or (2W+4) + W + (2W+4) + W = 88, 6W + 8 = 88 ====> 6W = 88-8 = 80 ====> W = = . Then L = 2*W + 4 = . Answer. The length is inches. The width is inches.

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I don't know what the two other authors were attempting to present - their solutions // their writings both were incorrect.