SOLUTION: he local bakery bakes more than a thousand 1-pound loaves of bread daily, and the weights of these loaves varies. The mean weight is 1 lb. and 4 oz., or 567 grams. Assume the stand
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-> SOLUTION: he local bakery bakes more than a thousand 1-pound loaves of bread daily, and the weights of these loaves varies. The mean weight is 1 lb. and 4 oz., or 567 grams. Assume the stand
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Question 1108082: he local bakery bakes more than a thousand 1-pound loaves of bread daily, and the weights of these loaves varies. The mean weight is 1 lb. and 4 oz., or 567 grams. Assume the standard deviation of the weights is 29 grams and a sample of 47 loaves is to be randomly selected.
(c) Find the standard error of this sampling distribution. (Give your answer correct to two decimal places.)
(d) What is the probability that this sample mean will be between 557 and 577? (Give your answer correct to four decimal places.)
(e) What is the probability that the sample mean will have a value less than 561? (Give your answer correct to four decimal places.)
(f) What is the probability that the sample mean will be within 8 grams of the mean? (Give your answer correct to four decimal places.)
You can put this solution on YOUR website! z is (xbar-mean)/sigma/sqrt(n)
z=10/(29/sqrt(47)=+2.36
z=-10/(29/sqrt(47)=-2.36
probability is 0.9817
less than 561 is z<-6/(29/sqrt(47)) or z< -1.418
probability of that is 0.0780
Within 8 grams of the mean is z+/-8*sqrt(47)/29 or +/-1.89
That is probability of 0.9412
