SOLUTION: 3y + 2z = 2 2x − y − 3z = 2 2x + 2y − z = 4 (x, y, z) =
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Question 1108013
:
3y + 2z = 2
2x − y − 3z = 2
2x + 2y − z = 4
(x, y, z) =
Answer by
Alan3354(69443)
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3y + 2z = 2
2x − y − 3z = 2
2x + 2y − z = 4
(x, y, z) =
=====================
|0 3 2 2| |2 -1 -3 2| |2 2 -1 4|
==========
Det = 0 -3*(-2+6) + 2*(4+2) = -12 + 12 = 0
No unique solution.
The 3rd equation is the sum of the 1st 2.