SOLUTION: In triangle BCD, an angle bisector is drawn from vertex B and intersects the opposite side at point E. If <CBE is 3x - 7 and <DBE is x + 23, what is the measure of <CBD? (please ex

Algebra ->  Triangles -> SOLUTION: In triangle BCD, an angle bisector is drawn from vertex B and intersects the opposite side at point E. If <CBE is 3x - 7 and <DBE is x + 23, what is the measure of <CBD? (please ex      Log On


   

Question 1107882: In triangle BCD, an angle bisector is drawn from vertex B and intersects the opposite side at point E. If
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In triangle BCD, an angle bisector is drawn from vertex B and intersects the opposite side at point E. If --------------
Draw the figure.
angle CBE = angle DBE because BE is a bisector.
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Equation::
3x-7 = x+23
2x = 30
x = 15
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angle CBD = angle CBE + angle DBE
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angle CBD = 3*15-7 + 15+23 = 38+38 = 76 degrees
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Cheers,
Stan H.
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