.
            The way is THIS:
Consider the system of 2 equations 
y =  ,              (1)
y - (-4) = m(x-4).       (2)
It is the same, as the system
y =
,              (1)
y - (-4) = m(x-4).       (2)
It is the same, as the system
y =  ,              (1)
y + 4 = m(x-4).          (2)
Find  the slope "m" under the condition that the system has a UNIQUE solution (x,y) = (4,-4).
For it, substitute expression for y,  y = m*(x-4)-4  into equation (1). You will get
m*(x-4) + 4 =
,              (1)
y + 4 = m(x-4).          (2)
Find  the slope "m" under the condition that the system has a UNIQUE solution (x,y) = (4,-4).
For it, substitute expression for y,  y = m*(x-4)-4  into equation (1). You will get
m*(x-4) + 4 =  .       (*)
Introduce new variable  u =
.       (*)
Introduce new variable  u =  .  Then the equation (*) takes the form
.  Then the equation (*) takes the form
 =
 =  ,
,
 =
 =  ,
,
 = 0.             (**)
The condition that the equation (**) has a unique solution in "u"  means that the discriminant of the equation (**) is equal to zero.
Write the discriminant of the quadratic equation (**) and equate it to zero:
d =
 = 0.             (**)
The condition that the equation (**) has a unique solution in "u"  means that the discriminant of the equation (**) is equal to zero.
Write the discriminant of the quadratic equation (**) and equate it to zero:
d =  =
 =  = 16 - 16m  ====>
the equation d = 0  becomes  16 - 16m = 0,  which implies  16m = 16  ====>  m = 1.
Answer.  The slope under the question is  m= 1,
      
         found without using derivatives.
 = 16 - 16m  ====>
the equation d = 0  becomes  16 - 16m = 0,  which implies  16m = 16  ====>  m = 1.
Answer.  The slope under the question is  m= 1,
      
         found without using derivatives.