Question 1107764: A person opens his wallet and finds that all the bills are $1 bills, $5 bills, or $10 bills. There are 38 bills in this person's wallet. There are 6 more $5 bills than $1 bills. If the total amount of bills is $238, how many $10 bills does this person have?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A person opens his wallet and finds that all the bills are $1 bills, $5 bills, or $10 bills. There are 38 bills in this person's wallet. There are 6 more $5 bills than $1 bills. If the total amount of bills is $238, how many $10 bills does this person have?
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Quantity Eq: O + F + T = 38 bills
Quantity Eq: F = O + 6
Value Eq::: O + 5F + 10T = 238 dollars
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Substitute for "F"
O + O+6 + T = 38
O + 5(O+6) + 10T = 238
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2O + T = 32
6O +10T = 208
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Modify for elimination:
6O + 3T = 96
6O + 10T = 208
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7T = 112
T = 16 (# of $10 bills)
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Cheers,
Stan H.
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