SOLUTION: A town’s population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population had increased to 52,070. Assume this trend continues.

Algebra ->  Finance -> SOLUTION: A town’s population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population had increased to 52,070. Assume this trend continues.      Log On


   

Question 1107760: A town’s population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population had increased to 52,070. Assume this trend continues.
A.The town's predicted population in the year 2020 is:
B.In what year will the town's predicted population be 103495 ?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
In two years, the population increased 6050.
The slope is 6050/2=3025.
In 2020, 10 years later, the population will increase 3025*10 or 30,250 from 2010, to 76,270.
103495=46020+3025x, which is the formula where x=years from 2010
57475=3025x
x=19 years
2029. ANSWER