Question 1107759: The father is 38 years older than the son. Ten years ago he was twice the age of the son. How old is the father and son now. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! let f be the father's age and s be the son's age
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f = s +38
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s +38 -10 = 2(s -10)
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s +38 -10 = 2s -20
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s = 48
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father is 86 and son is 48
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10 yeas ago the father was 76 and the son was 38
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76 = 2 * 38 = 76
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