SOLUTION: Please help. How to get the value of cot((3/2)x)? (if x=tan^-1(7/25)) Thank you.

Algebra ->  Trigonometry-basics -> SOLUTION: Please help. How to get the value of cot((3/2)x)? (if x=tan^-1(7/25)) Thank you.       Log On


   



Question 1107579: Please help.
How to get the value of cot((3/2)x)? (if x=tan^-1(7/25))
Thank you.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
FOR AN APPROXIMATE VALUE:
You use a calculator or computer to find tan%5E-1%287%2F25%29
and find that it is approximately
x=0.2730 (in radians) or x=12.642%5Eo .
Then, you multiply that times 3%2F2=1.5 to get
%283%2F2%29x=0.4095 or %283%2F2%29x=23.463%5Eo .
Finally, you find the cotangent of that angle.
If your calculator does not have cotangent,
you can find the approximate value for tangent,
tan%2823.463%5Eo%29=0.434 ,
and then find the approximate value for cotangent as
cot%2823.463%5Eo%29=1%2Ftan%2823.463%5Eo%29=1%2F0.434=appxoximately2.304

FOR AN EXACT VALUE:
Step 1:
Look for a list of trigonometric identities.
(A search brings up Wikipedia, and you find what you need there).
Step 2:
Figure out how to express %283%2F2%29x in a way that those trigonometric identities will help you find the answer.

Here is how I would do it:
%283%2F2%29x=%283x%29%2F2 or %283%2F2%29x=3%28x%2F2%29 .
Looking at the trigonometric identity formulas,
it seems that the easiest way is to first find sin%283x%29 and+cos%283x%29 ,
and then to find cot%28%283x%29%29%2F2%29 say theta=3x
and use cot%28theta%2F2%29=%281%2Bcos%28theta%29%29%2Fsin%28theta%29

At this point, I would check to make sure I had copied the problem right,
because it would be a much kinder problem if it were tan%5E-1%287%2F24%29 .
In that case, the angle would be as shown below:
with system%28sin%28red%28x%29%29=7%2F25%2Csin%28red%28x%29%29=24%2F25%29 .

x=tan%5E-1%287%2F25%29 is defined as the angle x , with -90%5Eo%3Cx%2C90%5Eo ,
such that tan%28x%29=7%2F25 .
As the tangent is positive, the angle must be positive.
So, x is a slightly smaller angle than the one in the drawing above,
the hypotenuse of the triangle for that case would be
sqrt%2825%5E2%2B7%5E2%29=sqrt%28625%2B49%29=sqrt%28674%29 ,
and we get ugly expressions for sine and cosine:
sin%28x%29=7%2Fsqrt%28674%29 and cos%28x%29=25%2Fsqrt%28674%29 .
Using the trigonometric identities for triple angles, we get

and

Then, using the half-angle identity for cotangent
cot%28%283x%29%2F2%29%22=%22%281%2Bcos%283x%29%29%2Fsin%283x%29%22=%22%22=%22%28337sqrt%28674%29%2B5975%29%2F6391