SOLUTION: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hr of labor to produce and the wreaths take 2 hrs. The labor available is limited to 80 h

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Question 110756: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hr of labor to produce and the wreaths take 2 hrs. The labor available is limited to 80 hrs per wk and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths. Then graph the system of inequalities.
Thank you.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(bouquets)(hrs per bouquet) + (wreaths)(hrs per wreath) < 80 (per week)
x*1 + y*2 < 80
x+%2B+2y+%3C=+80
2y+%3C=+-x+%2B+80
y+%3C=+-%281%2F2%29x+%2B+40 answer
(bouquets) + (wreaths) < = 60 items (per week)
x+%2B+y+%3C=+60
y+%3C=+-x+%2B+60 answer
+graph%28+500%2C+500%2C+-10%2C+90%2C+-10%2C+80%2C-%281%2F2%29x+%2B+40%2C-x+%2B+60%29+
The vertical axis is number of wreaths and hours per week working
on wreaths
The horizontal axis is number of bouquets and hours per week working on
bouquets
The operating area is under BOTH lines
If I solve
y+=+-%281%2F2%29x+%2B+40
y+=+-x+%2B+60
subtract the 2nd from the 1st
%281%2F2%29x+-20 = 0
x+=+40
y+=+20
This is the point where the lines meet